正项等比数列{an}中,a3a11=16,则log2a2+log2a12=_.

问题描述:

正项等比数列{an}中,a3a11=16,则log2a2+log2a12=______.

由题意可得log2a2+log2a12=log2a2a12=log2a3a11=log216=log224=4
故答案为:4