y=tan(x^2+e^x+ln7),求dy

分类: 作业答案 • 2022-05-03 10:34:08

问题描述：

答

∵y=tan(x^2+e^x+ln7)
∴dy=d(tan(x^2+e^x+ln7))
=(sec(x^2+e^x+ln7))^2*d(x^2+e^x+ln7)
=(sec(x^2+e^x+ln7))^2*(2x+e^x)dx.