y=cos(-2x+π/6)的单调递增区间
问题描述：
y=cos(-2x+π/6)的单调递增区间
答
y=cos(-2x+π/6)=cos(2x-π/6)
-π/2+2kπ-π/3+2kπ-π/6+kπ所以递增区间为[-π/6+kπ,π/3+kπ] k∈Z
答
y=cos(-2x+π/6)=cos(2x-π/6)
依题意
递增区间
π+2kπ