已知直角坐标系中,点P(x,y)满足x2−4+(y+3)2=0,则点P坐标为(  ) A.(2,-3) B.(-2,3) C.(2,3) D.(2,-3)或(-2,-3)

问题描述:

已知直角坐标系中,点P(x,y)满足

x2−4
+(y+3)2=0,则点P坐标为(  )
A. (2,-3)
B. (-2,3)
C. (2,3)
D. (2,-3)或(-2,-3)

x2−4
+(y+3)2=0,
x2−4=0
y+3=0

解得
x=2
y=−3
x=−2
y=−3

∴点P坐标为(2,-3)或(-2,-3).
故选:D.