等差数列an的项公式为an=2-3n,则它的公差d=

问题描述:

等差数列an的项公式为an=2-3n,则它的公差d=

an=2-3n
a(n-1)=2-3(n-1)
=2-3n+3
=5-3n
d=an-a(n-1)=2-3n-(5-3n)
=2-3n-5+3n
=-3
所以公差d=-3