等差数列{an}中,a4+a10+a16=30,则a18-2a14的值为_.

问题描述:

等差数列{an}中,a4+a10+a16=30,则a18-2a14的值为______.

∵a4+a10+a16=30,
∴3a10=30,
∴a10=10,
又∵a18-2a14=4d-a14=-a10=-10
故答案为-10.