已知 n>1且n属于N* ,求证logn(n+1)>logn+1(n+2)
问题描述:
已知 n>1且n属于N* ,求证logn(n+1)>logn+1(n+2)
答
logn(n+1)=lg(n+1)/lgnlg(n+1)(n+2)=lg(n+2)/lg(n+1)显然验证lg(n+1)/lgn 与 lg(n+2)/lg(n+1)大小即可同时减去1(lg(n+1)-lg n)/lgn (1与(lg(n+2)-lg(n+1))/lg(n+1) (2(lg(n+1)-lg n)=lg((n+1)/n)(lg(n+2)-lg(n+1))...