如图直线ab与cd相交于点o,od平分∠boe,∠aoe:∠eob=5:4求∠aoc
问题描述:
如图直线ab与cd相交于点o,od平分∠boe,∠aoe:∠eob=5:4求∠aoc
答
约等于55.4度
答
∵∠aoe:∠eob=5:4
∴∠eob=4/9×180
=80°
∠aoe=5/9×180
=100°
又∵od平分∠boe
∴∠doe=1/2∠boe
=1/2×80
=40°
∴∠aoc=∠cod-∠aoe-∠doe
=180-100-40
=40°
答:∠aoc的度数为40°.