若复数m+2i/1−i(m∈R,i是虚数单位)为纯虚数,则m=_.

问题描述:

若复数

m+2i
1−i
(m∈R,i是虚数单位)为纯虚数,则m=______.

m+2i
1−i
(m+2i)(1+i)
(1−i)(1+i)
=
m−2
2
+
m+1
2
i,根据纯虚数的概念得出
m−2
2
=0 
m+1
2
≠0
,解得m=2.
故答案为:2