y=sin(2x+π/4)的单调递减区间
问题描述:
y=sin(2x+π/4)的单调递减区间
答
令2kπ+π/2<2x+π/4<2kπ+3π/2(k∈Z)
得2kπ+π/4<2x<2kπ+5π/4(k∈Z)
即kπ+π/8<x<kπ+5π/8(k∈Z)
所以y=sin(2x+π/4)的单调递减区间是(kπ+π/8,kπ+5π/8)(k∈Z)
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