写出函数y=sin(2x-π6)的单调递减区间.
问题描述:
写出函数y=sin(2x-
)的单调递减区间. π 6
答
由
+2kπ≤2x−π 2
≤π 6
+2kπ,得3π 2
+kπ≤x≤π 3
+kπ,k∈Z.5π 6
∴函数y=sin(2x-
)的单调递减区间为[π 6
+kπ,π 3
+kπ],k∈Z.5π 6