(2+1) (22+1) (24+1) (28+1) (216+1) (232+1)+1

问题描述:

(2+1) (22+1) (24+1) (28+1) (216+1) (232+1)+1
2后面的2,4,8,16,32,都是2的次幂

(2+1) (22+1) (24+1) (28+1) (216+1) (232+1)+1
=(2-1)(22+1) (24+1) (28+1) (216+1) (232+1) +1
=2^64-1+1
=2^64