已知f(x)=12x(x≥4)f(x+1)(x<4),则f(log23)=( ) A.124 B.−238 C.111 D.119
问题描述:
已知f(x)=
,则f(log23)=( )
(x≥4)1 2x f(x+1)(x<4)
A.
1 24
B. −
23 8
C.
1 11
D.
1 19
答
∵f(x)=
,
(x≥4)1 2x f(x+1)(x<4)
∴f(log23)=f(log23+1)
=f(log26)=f(log26+1)
=f(log212)=f(log212+1)
=f(log224)=
=1 2log224
.1 24
故选A.