已知f(x)=12x(x≥4)f(x+1)(x<4),则f(log23)=(  ) A.124 B.−238 C.111 D.119

问题描述:

已知f(x)=

1
2x
(x≥4)
f(x+1)(x<4)
,则f(log23)=(  )
A.
1
24

B.
23
8

C.
1
11

D.
1
19

∵f(x)=

1
2x
(x≥4)
f(x+1)(x<4)

∴f(log23)=f(log23+1)
=f(log26)=f(log26+1)
=f(log212)=f(log212+1)
=f(log224)=
1
2log224
1
24

故选A.