已知函数f(x)=--cos3.14*x,x大于0,f(x+1)+1,x小于等于0,则f(4/3)+f(-4/3)的值

问题描述:

已知函数f(x)=--cos3.14*x,x大于0,f(x+1)+1,x小于等于0,则f(4/3)+f(-4/3)的值

楼主,3.14我直接写成π好不好
f(4/3)+f(-4/3)
=-cos(4π/3)+f(-1/3)+1
=cos(π/3)+f(2/3)+2
=cos(π/3)-cos(2π/3)+2
=1+1+2
=4