求证(sin2α-cos2α)^2=1-sin4α (sin2α-cos2α)^2 =1-2sin2acos2a =1-sin4a
问题描述:
求证(sin2α-cos2α)^2=1-sin4α (sin2α-cos2α)^2 =1-2sin2acos2a =1-sin4a
下面是你回答的 没看懂..能不能详细点
答
(sin2α-cos2α)^2
=(sin2α)^2+(cos2α)^2-2sin2αcos2α
=1-sin(2α*2)
=1-sin4α
我有没解释清楚的地方可以直接来问我!