若4sinα−2cosα5cosα+3sinα=10,则tanα的值为_.
问题描述:
若
=10,则tanα的值为______. 4sinα−2cosα 5cosα+3sinα
答
∵
=4sinα−2cosα 5cosα+3sinα
=10,4tanα−2 5+3tanα
∴tanα=-2.
故答案为:-2