若4sinα−2cosα5cosα+3sinα=10,则tanα的值为_.

问题描述:

4sinα−2cosα
5cosα+3sinα
=10,则tanα的值为______.

4sinα−2cosα
5cosα+3sinα
=
4tanα−2
5+3tanα
=10,
∴tanα=-2.
故答案为:-2