复数z=i/1−i(i为虚数单位)的虚部是_.
问题描述:
复数z=
(i为虚数单位)的虚部是______. i 1−i
答
∵复数z=
i 1−i
=
i•(1+i) (1−i)•(1+i)
=−
+1 2
i1 2
故复数z=
(i为虚数单位)的虚部是i 1−i
1 2
故答案为:
1 2