复数z=i/1−i(i为虚数单位)的虚部是_.

问题描述:

复数z=

i
1−i
(i为虚数单位)的虚部是______.

∵复数z=

i
1−i

=
i•(1+i)
(1−i)•(1+i)

=
1
2
+
1
2
i
故复数z=
i
1−i
(i为虚数单位)的虚部是
1
2

故答案为:
1
2