已知三点A(1,2),B(2,-1),C(2,2),E,F为线段BC的三等分点,则AE•AF= _ .

问题描述:

已知三点A(1,2),B(2,-1),C(2,2),E,F为线段BC的三等分点,则

AE
AF
= ___ .

∵A(1,2),B(2,-1),C(2,2),

AB
=(1,-3),
BC
=(0,3)

AE
=
AB
+
1
3
BC
=(1,-2)

AF
=
AB
+
2
3
BC
=(1,-1)

AE
AF
=1×1+(-2)×(-1)=3

故答案为:3