已知三点A(1,2),B(2,-1),C(2,2),E,F为线段BC的三等分点,则AE•AF= _ .
问题描述:
已知三点A(1,2),B(2,-1),C(2,2),E,F为线段BC的三等分点,则
•
AE
= ___ .
AF
答
∵A(1,2),B(2,-1),C(2,2),
∴
=(1,-3),AB
=(0,3),BC
=AE
+AB
1 3
=(1,-2),BC
=AF
+AB
2 3
=(1,-1),BC
∴
•AE
=1×1+(-2)×(-1)=3.AF
故答案为:3