如图,在△ABC中,AB=AC,BD平分∠ABC,若∠BDC=120°,则∠A的度数为(  ) A.110° B.100° C.80° D.60°

问题描述:

如图,在△ABC中,AB=AC,BD平分∠ABC,若∠BDC=120°,则∠A的度数为(  )
A. 110°
B. 100°
C. 80°
D. 60°

∵AB=AC
∴∠C=∠ABC
∵BD平分∠ABC
∴∠ABD=∠DBC=

1
2
∠ABC=
1
2
∠C,
∴∠ADB=∠C+∠DBC=3∠DBC=60°
∴∠DBC=∠ABD=20°
∴∠A=180°-20°-60°=100°.
故选B.