求下列函数的单调区间y=sin(x+π/3) y=cos2x
问题描述：
求下列函数的单调区间y=sin(x+π/3) y=cos2x
.
答
1) y=sin(x+π/3)
=> y'=cos(x+π/3)
y'>0时,cos(x+π/3)>0,=> 2kπ-π/2＜x+π/3 2kπ-5π/60时,sin2x 2kπ-π