1.y=(1-2x^2)/(1+2x^2)2.y=2x-根号下(x-1)

问题描述:

1.y=(1-2x^2)/(1+2x^2)
2.y=2x-根号下(x-1)

1.y=(1-2x^2)/(1+2x^2)=(-(1+2x^2)+2)/(1+2x^2)=-1+2/(1+2x^2)2/(1+2x^2)的值域为(0,2〕,所以原函数的值域为(-1,1〕;2.设t=根号下(x-1) ,则x=t平方+1,且t>=0;原式等价于y=2*(t^2+1)-t=2*t^2-t+2=2*(t-1/4)^2+15/82*...