f(x)=(2mx-m^2 1)/(x^2 1)(x∈R）AD BE CF=(AB BC CA) (BC/2 CA/2 AB/2)
问题描述：
f(x)=(2mx-m^2 1)/(x^2 1)(x∈R）AD BE CF=(AB BC CA) (BC/2 CA/2 AB/2)
Bx2^2-ax2)/(x1^2-ax1)>1 3AB BC CA)/2=0
答
a>0,f(x)=loga(x^2-ax)在(-1/2,0)上单调递增因为AB BC CA=0因为f（x）=2-（x分之3）AD BE CF=(AB BC CA) (BC/2 CA/2 AB/2)