非零实数x、y满足(x2+2009-x)(y2+2009-y)=2009,则x+2008y/2008x+y=_.

问题描述:

非零实数x、y满足(

x2+2009
-x)(
y2+2009
-y)=2009,则
x+2008y
2008x+y
=______.

当x+y=0,即x=-y时,(

x2+2009
-x)(
y2+2009
-y)=2009恒成立,
x+2008y
2008x+y
=
−y+2008y
−2008y+y
=
2007y
−2007y
=-1.
故答案为:-1