已知非零实数x,y满足等式x2-xy-2y2=0,则x/y的值为多少?
问题描述:
已知非零实数x,y满足等式x2-xy-2y2=0,则x/y的值为多少?
答
x² - xy - 2y² = 0
方程两边同除y²得:
(x/y)² -(x/y) - 2 = 0
(x/y + 1)(x/y -2) = 0
x/y = -1 或 x/y = 2