求y=sin(-2χ+π/3)的单调区间及周期
问题描述:
求y=sin(-2χ+π/3)的单调区间及周期
答
y=sin(-2x+π/3 )=-sin(2x-π/3 )(1)T=2π/2=π(2)增区间 :即求y=sin(2x-π/3) 的减区间2kπ+π/2≤2x-π/3≤2kπ+3π/22kπ+5π/6≤2x≤2kπ+11π/6kπ+5π/12≤x≤kπ+11π/12所以 函数y=sin(-2x+π/3 )的...