y=cosx(sinx-cosx)的周期最值
问题描述：
y=cosx(sinx-cosx)的周期最值
答
y=cosx(sinx-cosx)
= (1/2)sin2x - (1/2)(cos2x+1)
= (√2/2)sin(2x-π/4) -1/2
周期=π
最值
max = √2/2 -1/2
min =-√2/2 -1/2