两个正项数列{An}{Bn}中,已知An,Bn²,An+1成等差数列,Bn²,An+1,Bn+1²成等比数列.求证：数列{Bn}是等差数列
问题描述：
两个正项数列{An}{Bn}中,已知An,Bn²,An+1成等差数列,Bn²,An+1,Bn+1²成等比数列.求证：数列{Bn}是等差数列
答
an,（bn)^2,a(n+1)成等差数列2(bn)^2=an+a(n+1)--①由（bn）^2,a(n+1),(b(n+1))^2成等比数列(a(n+1))^2=[bnb(n+1)]^2∴a(n+1)=bnb(n+1)在①中有2(bn)^2=bn(b(n-1)+b(n+1))即2bn=b(n-1)+b(n+1)故{bn}为等差数列...