已知x^2-1/(x-2)(x-3)=A+B/x-2+C/x-3则A=?B=?C=?
问题描述：
已知x^2-1/(x-2)(x-3)=A+B/x-2+C/x-3则A=?B=?C=?
答
已知x^2-1/(x-2)(x-3)=A+B/x-2+C/x-3两边同乘以(x-2),得x^2-1/(x-3)=A(x-2)+B +C/(x-3) ×(x-2)令x=2,得-3=B,即B=-3两边同乘以(x-3),得x^2-1/(x-2)=A(x-3)+B (x-3)+C令x=3,得8=C即C=8令x=1,得0=A-B-C/2A=B+C/2=-3+4=...