若f(n)=[1/(n+1)]+[1/(n+2)]+[1/(n+3)]+``` ```+(1/2n),则f(n+1)-f(n)=

问题描述:

若f(n)=[1/(n+1)]+[1/(n+2)]+[1/(n+3)]+``` ```+(1/2n),则f(n+1)-f(n)=

[1/(2n+1)]-[1/(2n+2)]