已知两个等差数列{an},{bn}的前n项和之比为(2n+1)/(3n-7),则a9/b9等于?
问题描述:
已知两个等差数列{an},{bn}的前n项和之比为(2n+1)/(3n-7),则a9/b9等于?
答
a9/b9
=2a9*n/2b9*n
=[(a1+a17)*17/2]/[(b1+b17)*17/2]
=S17/T17
=(2*17+1)/(3*17-7)
=35/44