已知等差数列{an}{bn}的前n项和分别是Sn、Tn,若Sn/Tn=n/(n+1),则a9/b9=

问题描述:

已知等差数列{an}{bn}的前n项和分别是Sn、Tn,若Sn/Tn=n/(n+1),则a9/b9=

S17=17(a1+a17)/2=17a9
T17=17(b1+b17)/2=17b9
a9/b9=(S17/17)/(T17/17)=S17/T17=17/18