设函数f(x)=(x-1)(x-2)...(x-2014),则f'(2014)=多少
问题描述：
设函数f(x)=(x-1)(x-2)...(x-2014),则f'(2014)=多少
答
f'(2014)=2013!可以给一下具体过程或原理吗，刚学这一部分f'(x)=(x-1)'(x-2)…(x-2014)+(x-1)(x-2)'(x-3)…(x-2014)+…(x-1)(x-2)…(x-2013)'(x-2014)
+(x-1)(x-2)…(x-2013)(x-2014)'
f'(2014)=(2014-1)(2014-2)…(2014-2013)=2013!