已知a/b=c/d=e/f=2/3.若b-2d+f-3≠0,则a-2c+e-2/b-2d+f-3=

问题描述:

已知a/b=c/d=e/f=2/3.若b-2d+f-3≠0,则a-2c+e-2/b-2d+f-3=
thanks

a/b=c/d=e/f=2/3
a=(2/3)b
c=(2/3)d
e=(2/3)f
原式=[(2/3)b-2(2/3)d+(2/3)f-2]/(b+2d+f-3)
=(2/3((b+2d+f-3)/(b+2d+f-3)
=2/3