已知sinα=-7/25且α属于(3π/2,2π),求cosα和tanα
问题描述:
已知sinα=-7/25且α属于(3π/2,2π),求cosα和tanα
答
sinα=-7/25且α属于(3π/2,2π),cosα>0,tanα(sinα)^2+(cosα)^2=1,cosα=24/25,tanα=sinα/cosα=-7/24
已知sinα=-7/25且α属于(3π/2,2π),求cosα和tanα
sinα=-7/25且α属于(3π/2,2π),cosα>0,tanα(sinα)^2+(cosα)^2=1,cosα=24/25,tanα=sinα/cosα=-7/24