(a+b/a-b)²×(2a-2b/3a+3b)-(a²/a²-b²)÷(a/b)
问题描述:
(a+b/a-b)²×(2a-2b/3a+3b)-(a²/a²-b²)÷(a/b)
答
原式=[(a+b)²/(a-b)²]×[2(a-b)/3(a+b)]-a²/(a+b)(a-b)×b/a
=2(a+b)/3(a-b)-ab/(a+b)(a-b)
=[(2a+2b)(a+b)-3ab]/3(a+b)(a-b)
=(2a²+4ab+2b²-3ab)/(3a²-3b²)
=(2a²+ab+2b²)/(3a²-3b²)