已知{an}为等差数列,a2+a8=12,则a5=_.

问题描述:

已知{an}为等差数列,a2+a8=12,则a5=______.

∵{an}为等差数列,∴a2,a5,a8成等差数列,又a2+a8=12,
∴2a5=a2+a8=12,
∴a5=6.
故答案为:6.