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[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?

分类: 作业答案 • 2022-01-22 10:52:54
问题描述：

[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]=?

答

[sin(45°+θ)]/[cos(45°-θ)]-[cos(θ+60°)]/[sin(θ+30°)]
=[sin(45°+θ)]/[sin(45°+θ)]-[sin(θ+30°)]/[sin(θ+30°)]
=1-1
=0

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