(1)1-2cos^2 750° (2)化简 sin^2 π/16-cos^2 π/16

问题描述:

(1)1-2cos^2 750° (2)化简 sin^2 π/16-cos^2 π/16

答:
1)
1-2cos²750°
=-cos(750°×2)
=-cos1500°
=-cos(1440°+60°)
=-cos60°
=-1/2
2)
sin²(π/16)-cos²(π/16)
=-cos(2π/16)
=-cos(π/8)