式子sin4θ+cos2θ+sin2θcos2θ的结果是
问题描述:
式子sin4θ+cos2θ+sin2θcos2θ的结果是
答
sin^4θ+cos^2θ+sin^2θcos^2θ
=sin^4θ+sin^2θcos^2θ+cos^2θ
=sin²θ(sin²θ+cos²θ)+cos²θ
=sin²θ+cos²θ
=1