用换元法解分式方程2xx−1−5x−5x+3=0时,如果设xx−1=y,那么原方程可化为( ) A.2y2+3y-5=0 B.2y2-5y+3=0 C.y2+3y-5=0 D.y2-5y+3=0
问题描述:
用换元法解分式方程
−2x x−1
+3=0时,如果设5x−5 x
=y,那么原方程可化为( )x x−1
A. 2y2+3y-5=0
B. 2y2-5y+3=0
C. y2+3y-5=0
D. y2-5y+3=0
答
设
=y,则原方程化为2y2+3y-5=0.x x−1
故选A.