求积分：上限是派/2 下限是0 sin的三次方xcosxdx 和结果
问题描述：
求积分：上限是派/2 下限是0 sin的三次方xcosxdx 和结果
答
∫(0->π/2) (sinx)^3cosxdx
=∫(0->π/2) (sinx)^3dsinx
= [(sinx)^4/4](0->π/2)
=1/4
答
∫[0,π/2]sin^3xcosxdx
=∫[0,π/2]sin^3xdsinx
=(sin^4x)/4 [0,π/2]
=(sin^4（π/2))/4-(sin^4(0))/4
=1/4-0
=1/4