y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
问题描述:
y=根号2sin(2x-π)cos【2(x+π)】化简为Asin(wx+y)的形式.
答
sin(2x-π)=-sin(2x)
cos【2(x+π)】=cos(2x)
y=√2sin(2x-π)cos【2(x+π)】
=-√2sin(2x)cos(2x)
=-√2/2 * sin(4x)
=√2/2 * sin(4x+π)