若lgA=a,lgB=b,lgC=c,则(lgA^2)*[lg(B/2]*(lg√C)=?
问题描述:
若lgA=a,lgB=b,lgC=c,则(lgA^2)*[lg(B/2]*(lg√C)=?
答
(lgA^2)*[lg(B/2]*(lg√C)
=2logA*(lgB-lg2)*(1/2)lgC
=ac(b-lg2)