,函数y=sin(2x−π3)+lg[tan(x+π6)]的定义域是(区间)_.
问题描述:
,函数y=
+lg[tan(x+
sin(2x−
)π 3
)]的定义域是(区间)______. π 6
答
要使函数y=sin(2x−π3)+lg[tan(x+π6)]有意义,需满足sin(2x−π3)≥0tan(x+π6)>0x+π6≠π2+kπ,k∈Z解得,π6+kπ≤x≤2π3+kπ,k∈Z−π6+kπ<x<π3+kπ,k∈Z即 kπ+π6≤x<kπ+π3,k∈Z∴函数的定义域...