1/2+1/6+1/12+1/20+···+1/n(n+1)的值为(),其中n为自然数

问题描述:

1/2+1/6+1/12+1/20+···+1/n(n+1)的值为(),其中n为自然数

1/2+1/6+1/12+1/20+...+1/n(n+1)
=(1-1/2) + (1/2-1/3) + (1/3-1/4) + (1/4-1/5) +...+ (1/n-1/(n+1))
=1-1/(n+1)
=n/(n+1)