在△ABC中,BC=n平方-1,AC=2n,AB=n平方+1（n＞2的整数）.△ABC是直角三角形吗?说明理由.
问题描述：
在△ABC中,BC=n平方-1,AC=2n,AB=n平方+1（n＞2的整数）.△ABC是直角三角形吗?说明理由.
答
BC^2=(n^2-1)^2=n^4-2n^2+1AC^2=(2n)^2=4n^2AB^2=(n^2+1)^2 =n^4+2n^2+1显然,BC^2+AC^2=n^4-2n^2+1+4n^2=n^4+2n^2+1=AB^2所以△ABC...