试确定k的取值范围,使不等式组x-5x-7/5〉-2x-2 3/2k-1/2(x+1)〉x/2+k-1/2.(1)只有一个整数解
问题描述:
试确定k的取值范围,使不等式组x-5x-7/5〉-2x-2 3/2k-1/2(x+1)〉x/2+k-1/2.(1)只有一个整数解
(2)没有整数解
答
分数的用括号括一下,要不然看得很乱确定k的取值范围,使不等式组x-(5x-7)/5〉-2x-2(3/2)k-(1/2)(x+1)〉(x/2)+(k-1)/2x-(5x-7)/5〉-2x-2....①(3/2)k-(1/2)(x+1)〉(x/2)+(k-1)/2......②由①得x>-17/5由②得x