x的2n次方减1(n为正整数)
问题描述:
x的2n次方减1(n为正整数)
答
x^2n-1
=(x^n)²-1²
=(x^n+1)(x^n-1)
x的2n次方减1(n为正整数)
x^2n-1
=(x^n)²-1²
=(x^n+1)(x^n-1)