a,b两数满足a=根下b-2+(根号2-b)+7,则a的b次方的值为多少
问题描述:
a,b两数满足a=根下b-2+(根号2-b)+7,则a的b次方的值为多少
答
a = √(b-2) +√(2-b) + 7 ==> b = 2 a = 7 a^b = 7^2 = 49
a,b两数满足a=根下b-2+(根号2-b)+7,则a的b次方的值为多少
a = √(b-2) +√(2-b) + 7 ==> b = 2 a = 7 a^b = 7^2 = 49