已知：X的平方-1/（X-2）（X-3)=A+B/(X-2)+C/X-3,求ABC的值
问题描述：
已知：X的平方-1/（X-2）（X-3)=A+B/(X-2)+C/X-3,求ABC的值
答
(x^2-1)/{(x-2)(x-3) } = A + B/(x-2) + C(x-3)等式右边统分：{A(x-2)(x-3) + B(x-3) + C(x-2)} / {(x-2)(x-3)}= {A(x^2-5x+6) + B(x-3) + C(x-2)} / {(x-2)(x-3)}= {Ax^2-5Ax+6A + Bx-3B + Cx-2C} / {(x-2)(x-3)}= ...